How to test the state of a UISwitch

- by

We can use the isOn property of your switch to do this:

if (flickSwitch isOn) {
 statusLabel.text = @"The Switch is ON";
 } else {
 statusLabel.text = @"The Switch is OFF";
 }

Alternatively we can use the square-bracket notation like so:

if ([flickSwitch.isOn]) {
 statusLabel.text = @"The Switch is ON";
 } else {
 statusLabel.text = @"The Switch is OFF";
 }



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2 thoughts on “How to test the state of a UISwitch”

  1. You know what it’s like… a few months later this doesn’t work anymore, or it’s the other way round. I H-A-T-E Xcode and this Objective-C 5H1T so very very very much.

    That aside, here’s another solution which works (today that is):

    if (flickSwitch.on == YES) {
  // jump off a bridge
  } else {
  // take an overdose
  }

  2. There is another way by checking if the sender’s property isOn or not, like so:

        if ([sender isOn]) {
        // do something good
    } else {
        // do something else
    }

    This is useful if you don’t want to define the switch as a property. All you need to do is connect it to an action which will check the above.

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