How to find my own IP address in CentOS

Two commands come to the rescue: ip and ifconfig. Either does the trick:

#ifconfig eth0

eth0      Link encap:Ethernet  HWaddr 00:19:99:0D:D2:58  
          inet addr:87.106.181.234  Bcast:87.106.181.234  Mask:255.255.255.255
          inet6 addr: fe80::219:99ff:fe0d:d258/64 Scope:Link
          UP BROADCAST RUNNING MULTICAST  MTU:1500  Metric:1
          RX packets:14022830 errors:1 dropped:0 overruns:0 frame:1
          TX packets:17605482 errors:0 dropped:0 overruns:0 carrier:0
          collisions:0 txqueuelen:1000 
          RX bytes:6842851425 (6.3 GiB)  TX bytes:22015650673 (20.5 GiB)
          Interrupt:225 Base address:0x2000 

Slightly more parameters with ip, and slightly less output:

#ip addr show eth0

2: eth0:  mtu 1500 qdisc pfifo_fast qlen 1000
    link/ether 00:19:99:0d:d2:58 brd ff:ff:ff:ff:ff:ff
    inet 87.106.181.234/32 brd 87.106.181.234 scope global eth0
    inet6 fe80::219:99ff:fe0d:d258/64 scope link 
       valid_lft forever preferred_lft forever

The output on the second line is the IP address (in our example 87.106.181.234).

• http://www.cyberciti.biz/faq/howto-find-ip-address-on-centos-fedora-redhat-enterprise-linux/